Lapidary Work
lapidary work

College business math problem?
A jewelry company prepares and mounts precious stones. There are 10 lapidaries (who cut and polish stones) and 12 jewelers (who mount stones). Each employee works 7 hours each day. Each tray of agates requires 5 hours of cutting and polishing and 4 hours of mounting. Each tray of onyxes requires 2 hours of cutting and polishing and 3 hours of mounting. If the profit is $15 for each tray of agates and $10 for each tray of onyxes, how many trays of each stone should be processed each day to obtain the greatest profit?
I have figured the profit equation to be P=15x+10y where x is agates and y is onyxes. I know I want to maximize the profit equation.
Are the constraints what I have below?
5x+2y=10 (cut and polish constraint)?
4x+3y=12 (mount constraint)?
10x+12y≤154 (labor constraint)? I figured if each employee works 7 hours a day then 10+12=22 and 22*7= 154 hours max?
Please help me I'm stuck and I've tried to figure this problem out for a few hours!!!
5x+2y=10 (cut and polish constraint)?
4x+3y=12 (mount constraint)?
5, 2, 4, and 3 are hours so the 10 and 12 each need to be multiplied by 7
and the = should be ≤
The 10x+12y≤154 is not needed.
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Charles Schlueter's Decorated Presentation RAJA SAMADHI
lapidary work
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